8*n^2 + 8*n + 4

factorize

asked by guest
on Sep 27, 2024 at 2:17 pm



You asked:

Factor the expression: \(\displaystyle 8 \cdot {n}^{2} + 8 n + 4\)

MathBot Answer:

Factorization over the rational numbers:

\[4 \cdot \left(2 n^{2} + 2 n + 1\right)\]

Factorization over the complex numbers:

\[8 \left(n + \left(\frac{1}{2} - \frac{i}{2}\right)\right) \left(n + \left(\frac{1}{2} + \frac{i}{2}\right)\right)\]


\(i\) is the imaginary unit, defined as \(i^2 = -1\).