1.8(8-3)-2(1.05+1.2)/5

asked by guest
on Sep 26, 2024 at 5:08 pm



You asked:

Evaluate the expression: \(1.8 \cdot \left(8 - 3\right) - \frac{2 \cdot \left(1.05 + 1.2\right)}{5}\)

MathBot Answer:

\[1.8 \cdot \left(8 - 3\right) - \frac{2 \cdot \left(1.05 + 1.2\right)}{5} = \frac{81}{10} = 8.1\]

\[\begin{aligned}1.8 \cdot \left(8 - 3\right) - \frac{2 \cdot \left(1.05 + 1.2\right)}{5}& = \left(1 + \frac{8}{10}\right) \cdot \left(8 - 3\right) - 2 \cdot \left(1 + \frac{5}{100} + 1 + \frac{2}{10}\right) \cdot \frac{1}{5}\\& = \left(1 + \frac{4}{5}\right) \cdot \left(8 - 3\right) - 2 \cdot \left(1 + \frac{5}{100} + 1 + \frac{2}{10}\right) \cdot \frac{1}{5}\\& = \frac{9}{5} \cdot \left(8 - 3\right) - 2 \cdot \left(1 + \frac{5}{100} + 1 + \frac{2}{10}\right) \cdot \frac{1}{5}\\& = \frac{9}{5} \cdot 5 - 2 \cdot \left(1 + \frac{5}{100} + 1 + \frac{2}{10}\right) \cdot \frac{1}{5}\\& = 9 - 2 \cdot \left(1 + \frac{5}{100} + 1 + \frac{2}{10}\right) \cdot \frac{1}{5}\\& = 9 - 2 \cdot \left(1 + \frac{1}{20} + 1 + \frac{2}{10}\right) \cdot \frac{1}{5}\\& = 9 - 2 \cdot \left(1 + \frac{1}{20} + 1 + \frac{1}{5}\right) \cdot \frac{1}{5}\\& = 9 - 2 \cdot \left(\frac{21}{20} + 1 + \frac{1}{5}\right) \cdot \frac{1}{5}\\& = 9 - 2 \cdot \left(\frac{41}{20} + \frac{1}{5}\right) \cdot \frac{1}{5}\\& = 9 - 2 \cdot \frac{9}{4} \cdot \frac{1}{5}\\& = 9 - 2 \cdot \frac{9}{20}\\& = 9 - \frac{9}{10}\\& = \frac{81}{10}\end{aligned}\]

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