15*n^2 + 6*n + 1

factorize

asked by guest
on Sep 26, 2024 at 8:59 pm



You asked:

Factor the expression: \(\displaystyle 15 \cdot {n}^{2} + 6 n + 1\)

MathBot Answer:

Factorization over the real numbers:

\[15 \cdot \left(1 n^{2} + 0.4 n + 0.0666666666666667\right)\]

Factorization over the complex numbers:

\[15 \left(n + \left(\frac{1}{5} - \frac{\sqrt{6} i}{15}\right)\right) \left(n + \left(\frac{1}{5} + \frac{\sqrt{6} i}{15}\right)\right)\]


\(i\) is the imaginary unit, defined as \(i^2 = -1\).