Math Problem Solver

\[ 9\frac{3}{7} + 7\frac{4}{5} + 1\frac{3}{4} = \frac{2657}{140} = 18.97\overline{857142} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{9}{1}\), \(\frac{3}{7}\), \(\frac{7}{1}\), \(\frac{4}{5}\), \(\frac{1}{1}\), and \(\frac{3}{4}\) is \(140\). \[ \begin{aligned} 9\frac{3}{7} + 7\frac{4}{5} + 1\frac{3}{4} &= \frac{9 \cdot 140}{1 \cdot 140} + \frac{3 \cdot 20}{7 \cdot 20} + \frac{7 \cdot 140}{1 \cdot 140} + \frac{4 \cdot 28}{5 \cdot 28} + \frac{1 \cdot 140}{1 \cdot 140} + \frac{3 \cdot 35}{4 \cdot 35} \\ &= \frac{1260 + 60 + 980 + 112 + 140 + 105}{140} \\ &= \frac{2657}{140} \end{aligned} \]