e ^((−9x^4−x^2+1)/(6x^3−4x+10))
You asked:
Evaluate the expression: \({e}^{\frac{-\left( 9 \cdot {x}^{4} \right) - {x}^{2} + 1}{6 \cdot {x}^{3} - 4 x + 10}}\)
MathBot Answer:
Evaluated
\(\displaystyle {e}^{\frac{-\left( 9 \cdot {x}^{4} \right) - {x}^{2} + 1}{6 \cdot {x}^{3} - 4 x + 10}} = e^{\frac{- 9 x^{4} - x^{2} + 1}{6 x^{3} - 4 x + 10}} \)
Expanded
\[{e}^{\frac{-\left( 9 \cdot {x}^{4} \right) - {x}^{2} + 1}{6 \cdot {x}^{3} - 4 x + 10}} = e^{- \frac{x^{2}}{6 x^{3} - 4 x + 10}} e^{- \frac{9 x^{4}}{6 x^{3} - 4 x + 10}} e^{\frac{1}{6 x^{3} - 4 x + 10}}\]
Factored
\[{e}^{\frac{-\left( 9 \cdot {x}^{4} \right) - {x}^{2} + 1}{6 \cdot {x}^{3} - 4 x + 10}} = e^{- \frac{x^{2}}{6 x^{3} - 4 x + 10}} e^{- \frac{9 x^{4}}{6 x^{3} - 4 x + 10}} e^{\frac{1}{6 x^{3} - 4 x + 10}}\]
\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).
asked 1 year ago
active 1 year ago