$\sqrt{27}$ +2$\sqrt{75}$= K$\sqrt{3}$

Find K

asked by guest
on Nov 29, 2024 at 5:28 am



You asked:

Solve the equation \[\sqrt{27} + 2 \cdot \sqrt{75} = K \cdot \sqrt{3}\] for the unknown \(K\).

MathBot Answer:

The solution is: \[K = 13\]

\[\begin{aligned}13 \sqrt{3} &= \sqrt{3} K\\- \sqrt{3} K &= - 13 \sqrt{3}\\K &= 13\end{aligned}\]

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