Given the following equation:
Al: 29.98 g/mol Cl: 35.453 g/mol
Al(s) + Cl2(g) → AlCl3(s)
1. Balance the equation.
____Al(s) + ____Cl2(g) → ____AlCl3(s)
2. If 6 grams of Al was used to react with excess Cl2, determine the amount of AlCl3
formed. Show your solution and box the conversion factor/s used.
3. If 19 grams of Al reacts with 63 grams Cl2, determine the limiting reactant. How
much of the excess reactant will remain after the reaction?
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