x^-o,5

asked by guest
on Nov 23, 2024 at 3:38 am



MathBot Answer:

The sum of \({x}^{-o}\) and \(5\) is:

\[\begin{aligned}&=\left({x}^{-o}\right) + \left(5\right) \\\\ &= 5 + x^{- o} \\\\\end{aligned}\]

The difference of \({x}^{-o}\) and \(5\) is:

\[\begin{aligned}&=\left({x}^{-o}\right) - \left(5\right) \\\\ &= -5 + x^{- o} \\\\\end{aligned}\]

The product of \({x}^{-o}\) and \(5\) is:

\[\begin{aligned}&=\left({x}^{-o}\right) \cdot \left(5\right) \\\\ &= 5 x^{- o} \\\\\end{aligned}\]

The quotient of \({x}^{-o}\) and \(5\) is:

\[\begin{aligned}&= \frac{\left({x}^{-o}\right)}{\left(5\right)} \\\\ &= \frac{x^{- o}}{5} \\\\\end{aligned}\]

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