v=\left(1+\frac{1kg}{0.009kg}\right)\sqrt{2\cdot9{,}81\ m/s^2\cdot0{,}65m}

asked by guest
on Nov 29, 2024 at 1:24 am



Mathbot Says...

I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.