$\frac{10}{10+x}$-$\frac{1}{110-x-y}$=0
$\frac{5}{10+y}$-$\frac{1}{110-x-y}$=0
You asked:
Solve the system of equations:\[\begin{aligned}\frac{10}{10 + x} - \frac{1}{110 - x - y} &= 0\\\frac{5}{10 + y} - \frac{1}{110 - x - y} &= 0\end{aligned}\]
MathBot Answer:
The system of equations has one solution.
\[x = \frac{285}{4}, y = \frac{245}{8}\]