2^(2x+1) - 5 *(2x) + 2 = 0
You asked:
Solve the equation \({2}^{2 x + 1} - 5 \cdot 2 x + 2 = 0\) for the variable \(x\).
MathBot Answer:
The 2 solutions to the equation are: \[\begin{aligned}x &= \frac{0.898356640622957008728149216694901898383524684391 + \frac{2 \log{\left(2 \right)}}{5}}{2 \log{\left(2 \right)}} \approx 0.84802734\\x &= \frac{1.10903548889591249506757139433308250892080021498 + \frac{2 \log{\left(2 \right)}}{5}}{2 \log{\left(2 \right)}} \approx 1.0\end{aligned}\]