930.7÷93.07
-2c+3c-2c
1+2
solve the following inequality: $\frac{f}{2}$ +_25>45
if solution of recurrence relation aSn+bSn-1+cSn-2 = 6 is 3n+ 4n+ 2 , find a,b,c
x + 5% = 68.99
1/4+1/5+1/8
3b-3a-2b
2+2
