1411รท28
find the nature of the stationary points on the curve y=x^3-2x^2+1
SUBTRACT 14/16 FROM 8 10/16
SUBTRACT 13/15 FROM 14/15
6K^2-4K^3-1=0
54,000,000 %1
WHAT IS THE SUM OF THE GIVEN ILLUSTRATED FRACTIONS?
a=1 b=2 c=-1
2 a+ 2 b-3b-3c
6x+6y=9
5 4/15 + 14
