Solve using elimination.
2x + 8y = –20
–4x − 3y = –12
2÷1
expand f(Z)= 7Z -2 /z(z+1)(z-z) in Laurent's series valid for 1<|z+1|<3
5x + 3y = 3
x + 2y = 9
Find the equation of the line that passes through the following two points:
(-5, -7) and (-3, 6)
Group of answer choices
2x + 2y = –4
8x + 5y = –19
solve using elimination.
–x + 2y = 12
9x + 10y = 4
2a*3a*4a