(√24 − √54) × √6
0=e^{-2y}
3/5÷ (2/5− 0.25) + (1.5 ÷3/4) ÷ (3/10−4/5)
x=e^{-2y}
-4n-n=1
-4n-n
x=e^{-2t}
2n+m=1
-n+2m=1
SI TENGO COMO DATO UN LADO Y UN ANGULOS APLICO PITAGORAS ?
Imagine you are an engineer working on a project involving the deformation of a rectangular metal sheet under stress.
The stress ...
